Tentukan akar akar persamaan dari 3x²+5x-12=0 dengan melengkapkan kuadrat sempurna
#Pakai caranya
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#Pakai caranya
#No copas google (Report)
x = -3 atau x = 4/3
Penjelasan dengan langkah-langkah:
3x² + 5x - 12 = 0
3x² + 5x = 12 ->kedua ruas dibagi 3
x² + 5/3 x = 4
x² + 5/3 x + (5/6)² = 4 + (5/6)²
(x + 5/6)² = 144/36 + 25/36
(x + 5/6)² = 169/36
x + 5/6 = ± √(169/36)
x + 5/6 = ± 13/6
x + 5/6 = -13/6 atau x + 5/6 = 13/6
x = -13/6 - 5/6 x = 13/6 - 5/6
= -18/6 x = 8/6
= -3 x = 4/3
Penjelasan dengan langkah-langkah:
melengkapi kuadrat sempurna
3x² + 5x - 12 = 0
______________÷3
x² + 5/3x - 4 = 0
x² + 5/3 = 4
(x + 5/3/2)² - ... = 4
(x + 5/3 × 1/2)² - ... = 4
(x + 5/6)² - 25/36 = 4
(x + 5/6)² = 4 + 25/36
(x + 5/6)² = 144/36 + 25/36
(x + 5/6)² = 169/36
x + 5/6 = ±√169/36
x + 5/6 = ±13/6
x = -5/6 ± 13/6
x1 = -5/6 + 13/6 = 8/6 = 4/3
x2 = -5/6 - 13/6 = -18/6 = -3
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